A confined of gas at 10 has a pressure of 2.5 atm. What is its new pressure if the temperature is increased to 60?
P1T1=P2T2\frac{P_1}{T_1}= \frac{P_2}{T_2}T1P1=T2P2
P2=P1×T2T1P_2=\frac{P_1×T_2}{T_1}P2=T1P1×T2
P2=2.5×[273+60][273+10]=2.94atmP_2=\frac{2.5×[273+60]}{[273+10]}=2.94atmP2=[273+10]2.5×[273+60]=2.94atm
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