Answer to Question #261873 in General Chemistry for Manuel

Question

A 1.000L flask is filled with 1.000mol of H2(g) and 2.000mol of I2(g) at 448°C. The value of the equilibrium constant at 448°C is Kc = 50.5 for the reaction    

H2(g) + I2(g) ⇆ 2HI(g)

What are the equilibrium concentrations of H2, I2 and HI in moles per liter?

Answer 1

$Kc = [HI]^2/[H2]×[I2]$

[HI] = sqrt( Kc × [H2] × [I2] )

[HI] = sqrt( 54 × 0.025 × 0.017 ) mol/L

[HI] = 0.15149 mol/L = 0.15149 M