Answer to Question #260382 in General Chemistry for Bestie

Question

For the reaction A (aq) + B (aq) <---> C (aq) + D (aq), the equilibrium constant is 24.8 at 25oC and 38.3 at 50oC. What is the value of the change in Gibbs standard free enthalpy (in kJ) of this reaction at 75oC?

Answer 1

24.8—25

X—75

x=24.8*75/25=74.4

38.3—50

x—75

x=38.3*75/50=57.45

(74.4+57.45)/2=65,925