A 0.550 g sample is dissolved in water and conducted the following experiment to find its % w/w V3+ in the sample:
Step 1:
25.00 ml of 0.0400M K2C2O4, after acidification, is used to find the end point, requiring 22.70 ml of KMnO4(aq) for complete reaction. The reaction as follows:
__C2O42- (aq) +__MnO4- (aq) + __ H+ (aq) → ___CO2(g) +___Mn2+ (aq) + __H2O(l)
(unbalanced)
Step 2:
The aqueous solution of 0.550 g of the sample, after acidification, requiring 35.20 ml of the same KMnO4(aq) for complete reaction. The reaction as follows:
___V3+ (aq) + ___MnO4- (aq) + _____ H2O (l) → ___VO2+ (g) +___Mn2+ (aq) + ____H+(aq) from sample. (unbalanced)
(a) Balance the equations above. (3 marks)
(b) Calculate its % w/w V3+ in the sample. Show your calculation steps clearly. (7 marks)
___V3+ (aq) + ___MnO4- (aq) + _____ H2O (l) → ___VO2+ (g) +___Mn2+ (aq) + ____H+(aq)
__C2O42- (aq) +__MnO4- (aq) + __ H+ (aq) → ___CO2(g) +___Mn2+ (aq) + __H2O(l)
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