Answer to Question #259259 in General Chemistry for Tori

Question

198.3 g of water being heated by a bunsen burner, Suppose the water is heated from 15.7°C to 38.8°C on a Bunsen burner. How much heat energy in kJ was delivered by the burner in order to heat the water?

Answer 1

initial temperature of water =15.7°C

final temperature of water =38.8°C

Temperature Difference =23.1°C

1 °C= 4.186 kJ.

 The specific heat of water is 4179 J/kg K

Q =mcΔT

=(198.3/1000)

=0.1983kg* 4179 J/kg K*96.6966kJ

=80132.056 kJ