How many moles of ammonia is required to react with excess
sulfuric acid, H2SO4 to produced 1.4 grams ammonium
sulfate, (NH3)2SO4?
2NH3+H2SO4→(NH4)2SO42NH _ 3 +H _ 2 SO _ 4 →(NH _ 4 ) _ 2 SO _ 4 2NH3+H2SO4→(NH4)2SO4
The molar mass of ammonium sulfate is 132.14 g/mol.
Moles of ammonium sulphate =1.4132.14=0.011moles=\frac{1.4}{132.14}=0.011moles=132.141.4=0.011moles
Moles of ammonia =2×0.011=0.022moles= 2×0.011=0.022moles=2×0.011=0.022moles
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