what mass of water can be heated from 25°c to 50°c by the addition of 2825 j of heat
"T_1 = 25 \\;\u00b0C \\\\\n\nT_2 = 50 \\;\u00b0C \\\\\n\nQ = 2825 \\;J \\\\\n\nQ = mc\u0394T \\\\\n\nc=4.186 \\;J\/g\u00b0C \\\\\n\nm = \\frac{Q}{c\u0394T} \\\\\n\nm = \\frac{2825}{4.186(50-25)} = 26.99 \\;g"
Answer: 26.99 g
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