The solubility of Ca(OH) 2 ·8H 2 O in water at 25 ◦ C is 1.73 g per litre. What is the formality and molality of a saturated solution at 25 ◦ C, assuming it to be a very dilute solution? [Ca =
40, O = 16 and H = 1]
Molar mass of Ca(OH)2= 74.093 g/mol
So, number of moles of Ca(OH)
2
in 1 kg of water= 1.73/74.093
= 0.0233mol
1 mole of Ba(OH) 2 produces 2 moles of OH- ions
= 2×0.0233= 0.0466
Hence molality = 0.0466m
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