Answer to Question #252793 in General Chemistry for Paul

Question #252793

Hom many liters of water would need to be added to 900 grams of ammonium carbonate to produce 0.2M

Expert's answer

Moles of ammonium carbonate "=\\frac{900}{\n96.09}=9.4moles"

Volume of water = "\\frac{9.4}{0.2}=47L"

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