Answer to Question #252659 in General Chemistry for Nthabiseng

Question

Calculate the pH of a Sr(OH)2 solution prepared by dissolving 0.3211 g of Sr(OH)2 and making up to 250.00 mL solution

Answer 1

mole of Sr(OH)2 contains 2 moles of OH– .

Then, 0.042 * 2 = 0.084 mole of OH–

[OH–] = 0.084 mole / 0.25L = 0.336 M

pOH = –log 0.336= 0.47

pH = 14 – 0.47 = 14.47