Answer to Question #249576 in General Chemistry for mas

Question

Calculate the number of milliliters of 0.611 M Ba(OH)₂ required to precipitate all of the Ca²⁺ ions in 101 mL of 0.762 M CaCl₂ solution as Ca(OH)₂. The equation for the reaction is:

CaCl₂(aq) + Ba(OH)₂(aq) Ca(OH)₂(s) + BaCl₂(aq)

 mL Ba(OH)₂

Answer 1

Molar mass of Ba(OH)2= 171.34 g/mol

171.34×0.762= 130.56g

171.34×0.611= 104.69g

=130.36/104.69

=1.245ml