A hypothetical molecule, X–Y, has a dipole moment of 1.07 D
1.07 D and a bond length of 147 pm.
147 pm.
Calculate the percent ionic character of this molecule
All of this must be done using the correct units (cgs-esu), recognizing that 1 Debye = 1x10^-18 esu cm and that the charge on the electron is 4.80 x 10^-10 esu.
So, in this case, you have (after doing the needed conversions):
% ionic character = (1.83 x 10^-18 esu cm)/{(4.8 x 10^-10 esu)x(1.11x10^-8 cm)} x 100
100x{1.83/(4.8x1.11) = 34.3 %
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