Pentane is burnt with 96000cm^3 of oxygen gas at room temperature and pressure.
i. Write the balanced chemical equation for the reaction.
ii. Calculate the volume of carbon dioxide in cubic centimetres (cm^3) produced in the reaction at room temperature and pressure.
iii. Calculate the mass of Zinc needed to react with 50cm^3 0.8M of Hydrochloric acid.
C5H12+8O2→6 H2O+5 CO2
Molar mass of Oxygen = 31.998
96000/31.998
= 3000.19m
Molar mass of CO2 = 44.01 g/mol
3000.19× 44.01× 5/8
= 82523.98cm3
iii.Zn + HCl = H2 + ZnCl2
Molar mass of HCl = 36.458 g/mol
0.8× 36.458= 29.1664g
50/29.1664= 1.714mol
Mole ratio = 1:1
Molar mass of Zn = 65.38g/mol
1.714×65.38= 112.08g
Comments
All the answers are accurate and correct but you did not answer questions No. 3!
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