1. A 0.2500 g sample of a compound contain carbon, hydrogen and oxygen undergoes complete combustion to produce 0.3664 g of CO2 and 0.1500 g of H2O. Determine the empirical formula of this compound. [5 marks]
From the question given above, the following data were obtained:
Mass of compound = 0.25 g
Mass of CO₂ = 0.3664 g
Mass of H₂O = 0.15 g
Empirical formula =?
Next, we shall determine the mass of carbon, hydrogen and oxygen present in the compound. This can be obtained as follow:
For Carbon (C):
Mass of CO₂ = 0.3664 g
Molar mass of CO₂ = 12 + (2×16) = 44 g/mol
Mass of C = 12/44 × 0.3664
Mass of C = 0.1
C= 0.1/12= 0.0083
H= 0.02/1= 0.02
O= 0.13/16= 0.0081
Divide by the smallest
C= 0.0083/0.0081= 1
H = 0.02/0.0081= 2.47
O= 0.0081/0.0081= 1
Multiply by 2 to express in whole number
C = 1× 2= 2
H = 2.47× 2= 5
O = 1× 2= 2
Empirical formula : C2H5O2
Comments
Leave a comment