Answer to Question #246186 in General Chemistry for beza

Question #246186

what is the volume of 15.8 M nitric acid is needed to ensure 1.00 g sample copper completely reacts


1
Expert's answer
2021-10-04T05:09:59-0400

M(Cu) = 63.54 g/mol

n(Cu) =1.0063.54=0.0157  mol= \frac{1.00}{63.54} = 0.0157 \;mol

According to the reaction equation:

n(HNO3) = 4n(Cu) =4×0.0157=0.0629  mol= 4 \times 0.0157 = 0.0629 \;mol

Proportion:

15.8 mol – 1000 mL

0.0629 mol – x

x=0.0629×100015.8=3.98  mL4  mLx = \frac{0.0629 \times 1000}{15.8} = 3.98 \; mL ≈ 4 \;mL

Answer: 4 mL


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