What volume (mL) of 0.025 M HNO3 is necessary to titrate 19.6 mL of 0.042 M Ca(OH)2 solution to the endpoint?
The balanced reaction equation:
Ca(OH)2 + 2 HNO3 = Ca(NO3)2 + 2 H2O
The quantity of Ca(OH)2:
(0.042 M) * (0.01960 L) = 0.0008232 mol
So, the quantity of HNO3 is:
(0.0008232 mol) * 2 = 0.0016464 mol
Therefore, the volume must be:
(0.0016464 mol) / (0.025 M) = 0.065856 L = 65.856 mL
Answer: 65.856 mL
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