The smell of a burning match is due to the formation of sulfur oxides. The relevant reaction is S + O2 → SO2. If 4.8g of sulfur is burned in this manner, what mass of sulfur dioxide is produced?
Mole ratio of S : SO2 = 1:1
Molar mass of sulfur = 32.065
= 4.8/32.065 = 0.1497
Molar mass of SO2 = 64.066 g
= 0.1497× 64.066 = 9.59g
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