Question

Aqueous hydrobromic acid HBr will react with solid sodium hydroxide NaOH to produce aqueous sodium bromide NaBr and liquid water H2O. Suppose 9.71 g of hydrobromic acid is mixed with 6.5 g of sodium hydroxide. Calculate the maximum mass of sodium bromide that could be produced by the chemical reaction. Round your answer to 3

 significant digits.

Answer 1

$HBr+ NaOH\to NaBr+H_2O$

number of moles of HBr $= 9.71/80.91 = 0.12 \text{ moles}$

number of moles of NaOH $= 6.5/40 = 0.16 \text{ moles}$

The limiting reagent is HBr

$\therefore$ 0.12 moles of NaBr

0.12 moles of NaBr $= 0.12 × 102.89 = 12.3\ g$