It is desired to nake 1.00 Liter of 6.00 M nitric acud from concentrated 16.00 M HNO3.
a. How many moles of nitric acid are in 1.00 L of 6.00 M nitric acid?
Moles=Molarity×VolumeMoles=Molarity ×VolumeMoles=Molarity×Volume
Moles=1.00×6.00=6.00molesMoles=1.00×6.00=6.00molesMoles=1.00×6.00=6.00moles
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