Answer to Question #230044 in General Chemistry for Bella

Question

A chemist must dilute 23.4 mL of 444. mM (Molarity) aqueous sodium thiosulfate (Na2S2O3) solution until the concentration falls to 288 mM.  He'll do this by adding distilled water to the solution until it reaches a certain final volume.

Calculate this final volume, in milliliters. Round your answer to 3 significant digits

Answer 1

When performing dilution calculations, we use the formula;

M1V1 = M2V2

M1 = 444mM

M2 = 288mM

V1 = 23.4mL

V2 = ?

Thus;

444mM x 23.4mL = 288mL x V2

$\dfrac{444mM x 23.4mL}{288mM} = \dfrac{288mM x V2}{288mM}$

V2 $=\dfrac{444mM x 23.4mL}{288mM} = 36.075mL$