Answer to Question #229290 in General Chemistry for samikshak

Question

he equations used in this experiment would have to be modified slightly if an acid with Ka of 1.0x10^-3 or greater were used as an unknown. Assuming such a situation, explain the problems that would

Answer 1

Ka Is dissociation constant of acid.pKa Value determines if the acid is strong or weak acid.

The value of ka=1.0×10^-3,pKa=3,so the acid is weak acid.

In weak acid it is assumed that dissociation is very less with respect to initial concentration of acid at beginning.

If it is not done,then the calculation of pKa will be much complicated.