Question

The label on a stock bottle of HCl reads: Specific gravity 1.18; 36% HCl. How would you prepare 0.5dmcube of 3.0M HCl

Answer 1

Molar Mass of HCL = 36.458 g/mol

Molar Mass of 36% = $\frac{36}{100}×36.458 g/mol = 13.12g/mol$

$1dm^3= 1000ml$

$0.5dm^3= \frac{1000×0.5}{1}=500ml$

$\frac{3×500}{13.12g}=114g$

To prepare 3M of HCL you use 114 g