How many moles of gas are there in a sample occupying 1.74 L at 0.136 atm and 25°C?
PV = nRT
P = Pressure = 0.136atm
V= Volume =1.74 L
n = moles = ?
R= Gas Constant = 0.082057 L atm mol-1K-1
T = Temperature = 25 °C = 298 K
(0.136×0.25)=n(0.82057×298)(0.136×0.25) = n (0.82057×298)(0.136×0.25)=n(0.82057×298)
n=(0.136×0.25)(0.82057×298)n =\frac {(0.136×0.25)}{(0.82057×298)}n=(0.82057×298)(0.136×0.25)
n=0.00014moln = 0.00014moln=0.00014mol
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