A 45.41 gram sample of chromium is heated in the presence of excess oxygen. A metal oxide is formed with a mass of 66.36 g. Determine the empirical formula of the metal oxide.
Mass of Chromium = 45.41
Molar Mass of Chromium = 51.9961
= 0.8733 mol
Molar Mass of Oxygen = 15.999
= 66.35-45.41/15.999 = 1.3344
The ratio between
Chromium and Oxygen is2:3.So, the empirical formula is therefore Cr2O3
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