A solution of sodium hydroxide has a concentration of 60 g dm-3 . What is the molarity of the alkali?
[ Relative atomis mass : H=1, O=16, Na=23]
m= 60 g
M(NaOH)=23+16+1= 40 g/mol
"n = \\frac{m}{M} \\\\\n\nn=\\frac{60}{40}=1.5 \\;mol"
Molarity = 1.5 mol/L = 1.5 M
Answer: 1.5 M
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