Question

A solution of sodium hydroxide has a concentration of 60 g dm^-3 . What is the molarity of the alkali?

[ Relative atomis mass : H=1, O=16, Na=23]

Answer 1

m= 60 g

M(NaOH)=23+16+1= 40 g/mol

$n = \frac{m}{M} \\ n=\frac{60}{40}=1.5 \;mol$

Molarity = 1.5 mol/L = 1.5 M

Answer: 1.5 M