Answer to Question #219711 in General Chemistry for indika

Question

A divalent metal ion M²⁺ reacts with a unidentate ligand (L) to form a 1:1 complex ML₂²⁺. Calculate the concentration of M²⁺ in a solution prepared by mixing equal volumes of 0.20 M M²⁺ and 0.20 M L if the K_f is 1.0 x 10⁸

Answer 1

Solution

[M²⁺] = 0. 10 M, [L] = 0. 10 M

M2+ + L D ML²⁺ Kf = ( 0 [M2+] = 0.10 M, [L] = 0.10 M M2+ + L D ML2+ Kf = ( 0.10 –x )/x2

0.10>>x since kf is very large

1.0x10⁸= 0.10/x2, x = 3.2x10-5

Relative error = $(\frac{3.2\times10^{-5}}{0.10}) \times100 = 3.2\times10^{-2}$

[M²⁺] = 3.2x10^-5M