Answer to Question #219031 in General Chemistry for BreadKitty

Question

Ammonia is produced from its elements in a formation reaction. If 8.38 x 10²⁴ molecules of ammonia are produced, how many moles of nitrogen were used?

Answer 1

N₂ + 3H₂ = 2NH₃

amount n = Number of particles N / Avogadro constant N_A

According to the reaction equation for 2 mol of NH₃ are needs 1 mol of H₂

And then, calculate moles of H₂

n of H₂ $= (1× 8.38×10^{24})/(2× 6.023×10^{23} )$ = 6.96 moles

= 6.96 moles of N₂