Define the relation of the unit cell parameter and the atomic rafius
Let the edge length of the unit cell be a and the radius of the atom be r
FOR BCC LATTICE:
In bcc lattice the atoms on the body diagonal are in contact with each other
So length of diagonal = r + 2r + r = 4r
Also, body diagonal = "\\sqrt{3}" a
So, "\\sqrt{3}" a = 4 r
r = "\\dfrac{\\sqrt{3}a}{4}"
FOR FCC LATTICE:
In FCC lattice there are atoms at the corners and at the face centers . The nearest atoms touch each other.
So, distance between a corner and a face center particle = "\\dfrac{\\sqrt{2}}{2}a"
Also the distance between the corner and face center particle = 2r
So, 2r = "\\dfrac{\\sqrt{2}}{2}a"
r = "\\dfrac{\\sqrt{2}}{4}a"
Comments
Leave a comment