Question

Consider the reaction:

2NO(g)+Br2(g)⇌2NOBr(g) Kp=28.4 at 298 K

In a reaction mixture at equilibrium, the partial pressure of NO is 107 torr and that of Br2

is 122 torr. What is the partial pressure of NOBr in this mixture?

Answer 1

the partial pressure of NO is 107 torr and that of Br2

is 122 torr

$Kp= {products}/{reactants}$

28.4²= PNOBR/107²+122²

PNOBr= 80torr