Using the Duclos-traube rule determine how many times the surface activity of heptanol CH3CH2CH2OH is higher than the surface activity of ethanol CH3CH2OH
According to this rule, when the length of the hydrocarbon radical increases by one CH2 group, the surface activity of the substance increases by an average of 3.2 times. There are 3 more of them
3.2*3=9.6
the answer is 9.6 times more
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