500cm cube of a saturated solution of ALCL contains 26.6g dissolved in it at 45°c. What is the solubility in moles dm cube at this temperature
Volume = 500 cm3 which is equal to (500/1000)dm3 = 0.5 dm3
Moles of AlCl3 = 26.6/133.34 = 0.199 moles = 0.2 moles
Solubility = 0.2/0.5 = 0.4 moles/dm3
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