Answer to Question #208785 in General Chemistry for KPOPOII

Question #208785

Consider the titration of 50.00 mL of a mixture of NaI and NaBr with 0.0500 M silver nitrate. The first equivalence point was observed at 10.50 mL and the second at 25.50 mL. Calculate the molar concentration of the two salts in the sample


1
Expert's answer
2021-07-02T07:26:01-0400

Moles of mixture = 50.001000×0.0500=2.5×103\frac{50.00}{1000}×0.0500=2.5×10^{-3} Moles



Molarity = MolesVolume\frac{Moles }{Volume}


Molarity = 2.5×1030.0105=0.238M\frac{2.5×10^{-3}}{0.0105}=0.238M


Molarity =2.5×1030.0255=0.098M=\frac{2.5×10^{-3}}{0.0255}=0.098M


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