A 26 mal solution containing 2.0 M HClO3 is mixed with a 40mL solution containing 0.5 M NaOH. What is the pH of the resulting mixture ?
Reaction:
"HClO_3" is a strong aciid
"HClO_3+NaOH=NaClO_3+H_2O"
"\\nu(NaOH)=0mol"
"\\nu(HClO_3)=(0.052-0.02) mol=0.032 mol"
Total volume:
"V = V_1+V_2=66ml=.066L"
"C(HClO_3)=[H^+]=\\nu(HClO_3)\/V=0.485M"
"pH=-lg[H^+]=0.314"
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