Answer to Question #206737 in General Chemistry for Jay

Question

calculate the mass of H2 needed to react with 5.6 g of N2

Answer 1

3H₂ + N₂ $\to$ 2NH₃

1 mole of N₂ react with 3 moles of H₂

5.6g of N₂ means moles of N₂ = 5.6/28.013 = 0.199 moles

So moles of H₂ needed = 3×0.199 = 0.597mol

Mass of H₂ needed = 0.597 × 1.00784 = 0.601g