Answer to Question #205400 in General Chemistry for Isolomuzi

Question

2.In a redox reaction

Fe 2 O 3 + KNO 3 + KOH = K 2 FeO 4 + KNO 2 + H 2 O

find an oxidizing agent and a reducing agent, arrange the coefficients by any method (electronic or ion-electronic balance).

Answer 1

Now the oxidation number of Fe in reactant side is +3 but it increases to +6 on the product side so it oxidized hence it will behave as a Reducing agent.

The oxidation number of K in reactant side is +3 but it decreases to +1 on the product side so it reduced hence it will behave as a Oxidizing agent.

The balance chemical equation of the above is:

$Fe_2O_3+2KNO_3+2KOH \longrightarrow 2K_2FeO_4+KNO_2 +H_20$