Question #205321

How much heat is required to warm 1.60 L of water from 22.0 ∘C to 100.0? (Assume a density of 1.0g/mL for the water.)    

Express your answer in joules to two significant figures.



1
Expert's answer
2021-06-10T03:33:23-0400

q=1600g×(10022C)×(4.184)q= 1600g × (100-22C) × (4.184 )

q=5.9×102Jq=5.9×10 ^{2}J


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