Question

What mass of AlF₃ is produced when 168 grams of Al is consumed?

Answer 1

Solution

Al_(s)+F_2(g)➡️AlF_3(s)

1mole Al produces 1 mole AlF₃

RAM of Al=27g, F=19g

RFM of AlF₃=84g

No of moles = $\frac{Mass}{RFM}=\frac{168}{27}$

= 6.2 moles

6.2 moles of Al=6.2 moles of AlF₃

Mass= Number of moles$\times RFM$

$6.2\times84=520.8$

Mass of AlF₃ produces is 520.8g