Question

formic acid, HCOOC, can decompose to fom carbon monoxide gas, CO, and liquid water. if 3.85 L of CO was collected by downward displacement of water at 25.0 degree celcius and 689 mmHg how many grams of formic acid were reacted

Answer 1

Ans:- Reaction of Decomposition of Formic Acid $(HCOOH)$

$HCOOH \ \ \ \to \ \ \ CO(gas)\ \ \ + (liq. )H_2O$

Carbon Mono Oxide was collected at temperature $(T)$$=25+273=298K$ and at Pressure$(P)=689\ mmHg$ and having Volume$(V)=3.85 \ L$

Value of Gas Constant$\ =62.363\ mmHg.L.K^{-1}⋅mol^{−1}$

Ideal Gas equation

$PV=nRT\\$

$n=\dfrac{PV}{RT}$

$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ n=\dfrac{689\times3.85}{62.363\times298}=0.1427\ mol$

$0.1427 \ mol$ of Carbon Mono Oxide was formed by the decomposition of formic acid $(HCOOH)$

So, According to Stoichiometry

$1\ mol$ of formic acid react to form = $1\ mol$ of Carbon Mono Oxide

Hence $0.1427 \ mol$ of formic Acid $(HCOOH)$ was reacted

Therefore Gram of Formic Acid $(HCOOH)$ react$=0.1427\times46=6.5642\ gm$