What is the pressure of 0.33 moles of nitrogen gas, if ita volume is 15.0 L at -25.0⁰C
Using the ideal gas law "PV =nRT" , we find that the pressure will be "P =\\frac{nRT}{V}" . Then, we'll substitute and find the pressure, using T = -25 °C = 248.15 K and R = 0.0821 "\\frac{atm\\cdot L}{mol \\cdot K}" :
"P =\\frac{nRT}{V} = \\frac{(0.33\\,\\cancel{mol})(0.0821\\frac{atm\\cdot \\cancel{L}}{\\cancel{mol \\cdot K}})(248.15\\,\\cancel{K})}{15.0\\,\\cancel{L}} = 0.4482\\,atm"
In conclusion, the pressure of this gas is P=0.4482 atm.
Reference:
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