Question

Two oxide of a metal contained 71.2% and 78.8% respectively. Show that this information illustration the law of multiple proportion

Answer 1

full information is not given so , we will take an example to get the way to solve these types of problems

The percentage of metal in two metal oxides, A and B is 74.2% and 59%, respectively. Show that the law of multiple proportions is obeyed.

$\def\arraystretch{1.5} \begin{array}{c:c:c} Metal \ oxides & percentage \ of \ metal & percentage \ of \ oxygen\\ \hline A & 74.2 & 25.8 \\ \hdashline B & 59 & 41 \end{array}$

In A, 74.2 g of metal combines with 25.8 g of oxygen

combines with 1 g of oxygen

=$\frac{74.2}{25.8}=2.87g$

In B, 59 g of metal combines with 41 g of oxygen

And combines with 1 g of oxygen

=$\frac{59}{41}=1.43g$

∴ The ratio by weight of metal combining with fixed mass of oxygen in A and B

=2.87:1.43=2:1

Hence, law of multiple proportions is obeyed