The pressure inside a container is 77 atm at a temperature of 570C. What would the pressure be at 75o C?
P1/T1=P2/T2P_1/T_1=P_2/T_2P1/T1=P2/T2
P1=77atm,T2=57+273=330KP_1=77atm, T_2=57+273=330KP1=77atm,T2=57+273=330K
P2=?,T2=75+273=348KP_2=?, T_2=75+273=348KP2=?,T2=75+273=348K
77/330=P2/34877/330=P_2/34877/330=P2/348
P2=77×348330=81.2atmP_2=\frac{77\times 348}{330}=81.2atmP2=33077×348=81.2atm
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