Question

A balloon contains 46.3 L of Helium at 42 oC, and 2.01 atm is released into the air. At a certain altitude, the temperature falls to 21 oC, and the pressure falls to 0.25 atm. What is the volume of the balloon under these conditions?

A. 3.5 L

B. 35.0 L

C. 350 L

D. 3500 L

E. None of the Above

Answer 1

We have two conditions:

First condition:

$V_1=46.3l$

$T_1=42^0 C$

$P1=2.01atm$

Second condition:

$letV_2=V_2$

$T_2=21^0C$

$P_2=0.25atm$

Now by the help of gas equation:

$\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}$

$\dfrac{2.01\times46.3}{42}=\dfrac{0.25\times V_2}{21}$

$V_2=186.126l$

So our answer is Option E means none of the above is correct.