Given the reaction: 4 NH3(g) + 5 O2(g) —> 4NO (g) + 6H2O When 1.20 mole of ammonia reacts, how many moles of water are produced?
"\\boxed{4 NH_3(g) + 5 O_2(g) \\rightarrow 4NO (g) + 6H_2O }"
According to the stoichiometric equation of the reaction we see that
4 moles ammonia produces 6 moles of H2O
"\\implies" 1 mole ammonia produce "6\\over 4" mole H2O
So 1.20 mole ammonia produce
"1.20\\times{6\\over 4 } =1.8" mole H2O(water)
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