Question

Given the reaction: 4 NH3(g) + 5 O2(g) —> 4NO (g) + 6H2O When 1.20 mole of ammonia reacts, how many moles of water are produced?

Answer 1

$\boxed{4 NH_3(g) + 5 O_2(g) \rightarrow 4NO (g) + 6H_2O }$

According to the stoichiometric equation of the reaction we see that

4 moles ammonia produces 6 moles of H₂O

$\implies$ 1 mole ammonia produce $6\over 4$ mole H₂O

So 1.20 mole ammonia produce

$1.20\times{6\over 4 } =1.8$ mole H₂O(water)