Answer to Question #193052 in General Chemistry for Maddie Dalton

Question #193052

What is the heat required to vaporize 90.8 g of liquid ethanol, C2H5OH, at its boiling point? The ΔH° of vaporization of ethanol is 39.3 kJ/mol. Use a molar mass with at least as many significant figures as the data given.

Answer in kJ units


1
Expert's answer
2021-05-17T04:20:31-0400

"Moles =\\frac{ 90.8 g }{46.07 g\/mol }= 1.971\n mol"


"\u2206H\u00b0= 1.971mol \u00d7 39.3 kJ\/mol = 77.4603kJ"



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