Calculate the heat of hydrogenation of ethane 𝐶2𝐻4 using the following reactions:
2𝐶 (𝑔𝑟𝑎𝑝ℎ𝑖𝑡𝑒) + 3𝐻2 (𝑔) → 𝐶2𝐻6 (𝑔) ∆𝐻𝑓 = −84.5 𝑘𝐽/𝑚𝑜𝑙
2𝐶(𝑔𝑟𝑎𝑝ℎ𝑖𝑡𝑒) + 2𝐻2 (𝑔) → 𝐶2𝐻4 (𝑔) ∆𝐻𝑓 = 52.3 𝑘𝐽/mol
Reaction of heat of hydrogenation of ethane:
"C_2H_4+H_2\\Rightarrow C_2H_6"
Given that:
Equation .1.
"2C+3H_2\\Rightarrow C_2H_6:\\Delta H_1=-84.5KJ\/mol"
Equation .2.
"2C+2H_2\\Rightarrow C_2H_4:\\Delta H_2=" "52.3KJ\/mol"
Now to form the main equation we have to subtract equation 2 from equation 1:
So heat of hydrogenation"=" "\\Delta H_1-\\Delta H_2"
"=-84.5-52.3=-136.8KJ\/mol"
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