Question #192897

How many ml of water should be added to 375ml of a solution containing 0.5g of benzalkonium chloride to make 1 :5000 solution?


1
Expert's answer
2021-05-13T04:57:29-0400

1 : 5000 means 1g in 5000 mL of solution


1g0.5g=5000mLXmL\frac{1g}{0.5g} = \frac{5000 mL}{ X mL }


X = 2500 mL of 1 : 5000 of w/v solution containing 0.5 g of benzalkonium chloride

2500 mL - 375 mL = 2125 mL


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