Answer to Question #191203 in General Chemistry for Kayla

Question #191203

A gas with an initial pressure of 15.7 atm was allowed to expand to a volume of 15.2 L and a new pressure of 6.6 atm. What was the original volume (in L) of the gas?


1
Expert's answer
2021-05-12T06:40:10-0400

P1V1=P2V2P_1V_1 =P_2V_2


15.7atm×V2=6.6atm×15.2L15.7atm×V_2=6.6atm×15.2L


V2=6.6atm×15.2L15.7atmV_2=\frac {6.6atm ×15.2L}{15.7atm}


V2=6.4LV_2=6.4L


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