How many grams of ammonium chloride (NH4Cl) will you add to 250.mL of water to make a 0.577 M solution?
0.577M×0.577M\times0.577M× 53.49g1mole53.49g\over1mole1mole53.49g ×\times× 250ml1000ml250ml\over 1000ml1000ml250ml =7.49g=7.49g=7.49g
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