Question #189333

An aqueous solution of ferric hydroxide has a specific gravity of 1.25 and a weight fraction of

solute equal to 0.10. Calculate:

a) % solute by mole

b) Molality of the solution

c) Normality of the solution

d) ppb of solute


1
Expert's answer
2021-05-06T07:37:24-0400

i) Moles of Fe(OH)2=0.093moles0.093moles


ii)Molarity of the Solution =1.03M1.03M


iii)Normality of the solution=3.5M3.5M


iv)ppb of solute=105PPm10^{5} PPm


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