Calculate the mass of water formed when 2.6 moles of hydrogen reacts with excess oxygen gas.
2H2+O2>2H2O
2.6 moles of hydrogen produces 2.6 mol of water
so
2.6= Mass of H2O Molar mass2.6=x18⇒x=45g2.6=\dfrac{\text{ Mass of } H_2O}{\text{ Molar mass}} \\[9pt] 2.6=\dfrac{x}{18}\Rightarrow x=45g2.6= Molar mass Mass of H2O2.6=18x⇒x=45g
Hence The mass of the water formed is 45 g.
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