Calculate the mass of water formed when 2.6 moles of hydrogen reacts with excess oxygen gas.
2H2+O2>2H2O
2.6 moles of hydrogen produces 2.6 mol of water
so
"2.6=\\dfrac{\\text{ Mass of } H_2O}{\\text{ Molar mass}}\n\\\\[9pt]\n 2.6=\\dfrac{x}{18}\\Rightarrow x=45g"
Hence The mass of the water formed is 45 g.
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